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A 55 kg box slides across the floor by a force of 25N.

a.) How large a friction force impedes the motion of the box?
b.) How large is the normal force?
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1 Answer

a) If the velocity is a constant, then a = 0, and the friction force is balanced with 25 N force. So, the friction force = 25 N.
b) The normal force = mg = 55*9.8 = 539 N