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Need some quick help with this. ( Preferable walk through instead of giving me an answer I want to know how to do this)

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Write an Equation of the perpendicular to y = 3x + 1 Passing though (0,4)
The line you want has a y-intercept already given, at x=0, the y-axis, y=4. Thank you Nataliya D.
Its slope must be -1/3 the negative of the reciprocal of the slope of 3 of the given line
y=-(1/3)x+4

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.... a y-intercept already given, at x=0, the y-axis, y=4. ....