im falling algebra so please help me guys
Alternate way of doing this using the point-slope formula.
Since y = -3x + 1 is in y=mx + b format, the slope is -3.
m = -3
The slope of the line perpendicular to y = -3x + 1 must be -(1/-3), or 1/3, since m_{1} = -1/m_{2}.
Point - slope formula:
y - y1 = m (x - x1).
y - 4 = (1/3) (x - 1)
y - 4 = (1/3)x - 1/3
y = (1/3)x - 1/3 + 4
y = (1/3)x - 1/3 + 12/3
y = (1/3)x + 11/3
Since y = -3x + 1 is in y=mx + b format, the slope is -3.
m = -3
The slope of the line perpendicular to y = -3x + 1 must be -(1/-3), or 1/3, since m_{1} = -1/m_{2}.
Point - slope formula:
y - y1 = m (x - x1).
y - 4 = (1/3) (x - 1)
y - 4 = (1/3)x - 1/3
y = (1/3)x - 1/3 + 4
y = (1/3)x - 1/3 + 12/3
y = (1/3)x + 11/3
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