im falling algebra so please help me guys

Alternate way of doing this using the point-slope formula.

Since y = -3x + 1 is in y=mx + b format, the slope is -3.

m = -3

The slope of the line perpendicular to y = -3x + 1 must be -(1/-3), or 1/3, since m

Point - slope formula:

y - y1 = m (x - x1).

y - 4 = (1/3) (x - 1)

y - 4 = (1/3)x - 1/3

y = (1/3)x - 1/3 + 4

y = (1/3)x - 1/3 + 12/3

y = (1/3)x + 11/3

Since y = -3x + 1 is in y=mx + b format, the slope is -3.

m = -3

The slope of the line perpendicular to y = -3x + 1 must be -(1/-3), or 1/3, since m

_{1}= -1/m_{2}.Point - slope formula:

y - y1 = m (x - x1).

y - 4 = (1/3) (x - 1)

y - 4 = (1/3)x - 1/3

y = (1/3)x - 1/3 + 4

y = (1/3)x - 1/3 + 12/3

y = (1/3)x + 11/3

## Comments