Search
Ask a question
0

The number of victories they had was three less than six times the number of losses....

At the end of the 2000 WNBA regular season, the Houston Comets had 22 more victories than losses.  The number of victories they had was three less than six times the number of losses.  How many regular season games did the Houston Comets play during the 2000 WNBA season?
 
Need equation and answer

1 Answer by Expert Tutors

Tutors, sign in to answer this question.
Vivian L. | Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACHMicrosoft Word/Excel/Outlook, essay comp...
3.0 3.0 (1 lesson ratings) (1)
0
Hi Annie;
x=quantity of losses
x+22=quantity of victories
 
6x-3=x+22
Let's isolate x...
Let's add 3 to both sides...
3+6x-3=x+22+3
6x=x+25
Let's subtract x from both sides...
-x+6x=x+25-x
5x=25
x=5
5+22=total quantity of games=27
 
Let's check our results...
6x-3=x+22
6(5)-3=5+22
30-3=27
27=27