HI Aubry; 4x-7≥1 Let's add 7 to both sides... 7+4x-7≥1+7 4x≥8 Let' divide both sides by 4... (4x/4)≥(8/4) x≥2 Please do not forget... If I had multiplied either side by a negative number, the ≥ would have become ≤. 10/7/2013 | Vivian L. Comment