Jamark, it doesn't seem logical that a camera case would cost six times the amount of the camera itself. I believe you might have misunderstood and reworded the question.
Was the problem originally written something like this:
A camera with case costs 91.98. If the cost of the case itself is 6x the cost of the camera, how much does the case cost?
Solution: [let x = cost of the camera]
1) The cost of the camera (x) plus the cost of the case (6x) = 91.98
2) x + 6x = 91.98
3) 7x = 91.98
4) Divide 91.98 by 7 to get the value of x
5) x = 13.14
6) The cost of the camera (x) is 13.14. The cost of the case (6x) is therefore 6 * 13.14 = 78.84
Check your work!
7) Replace 13.14 for 'x' in the equation [step 2) above]
8) (13.14) + (6*13.14) = 91.98
9) 13.14 + 78.84 = 91.98
10) 91.98 DOES = 91.98
The cost of the camera = 13.14
The cost of the case = 78.84
*After you solve the equation, always reread the original question to ensure you answer what the problem is asking!
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