Let F (x) = integral from 0 to x^(1/3) of function sq root (1 + t^4) dt. F'(0) = ?
Solution manual says: F (x) = f(g(x)), where g(x) = x^(1/3) and f (z) = integral from 0 to z of function sq root (1+t^4) dt. Then they apply chain rule. Do not understand