use the y intercept and slope to sketch the graph of the equation

-4 - 16 = -20

-20x=-12

-10x=-6

-5x=-3

-x=-3/5

x=3/5

use the y intercept and slope to sketch the graph of the equation

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Oakton, VA

-4 - 16 = -20

-20x=-12

-10x=-6

-5x=-3

-x=-3/5

x=3/5

Bristow, VA

Assuming there are no typos: -4x-16x = -12

So... -20x = -12

Divide both sides by -20 to isolate your variable

and x = -12/-20 or 3/5 =x

lines generally take the form of y= mx + b (where m represents the slope and b the y intercept)

in the equation x = 3/5 no matter what y equals x will be the same.

So what you get is a vertical line at 3/5. This line will not have a y-intercept as it never crosses that axis. It's slope will also be undefined.

Oconomowoc, WI

I think that one of your x terms needs to be y.

lets assume your equation was -4y-16x = -12

we know that the slope intercept formula is y = mx + b

so we need to get your equation into the same format

-4y -16x + 16x = -12 + 16x

-4y = 16x -12

divide each side by -4

-4y/(-4) = (16x - 12)/(-4)

which gives you (the slope intercept equation for the line)

y = -4x + 3

using this line and slope intercept formula you know that the slope, m =-4 and your y-intercept , b = 3

your y-intercept is the value of y on your line when x = 0 so you have one point (0,3)

You need another point to draw/graph the line

Now another way of looking at your slope is knowing that it is equal to the change of y divided by the change in x

m = (y_{1}-y_{2})/(x_{1}-x_{2})

since your slope is -4 which can be written as -4 = -4/1 using the concept above you could take your point (0,3) and know that if you moved y 4 points down on the graph and x one point to the right you would get the next point (1,-1). You can then graph your line using those two points

OR you could substitute in different values for x into the slope intercept equation for the line and determine a new y

y = -4x + 3

using x = 1, y = -4(1) + 3 = -4 + 3 = -1 point (1,-1)

Which is the same as the value of the point you would get from moving along the graph. I hope this helps

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