_{2}-y

_{1) }/ (x

_{x}-x

_{1})

must be done in point slope form

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Let us remember that the slope intercept form of an equation equals: y = mx +b, where "m" = slope of the line, and "b"= intercept of the line,

Now, the formula for the slope of a line can be found by, m = (rise)/(run) = (y_{2}-y_{1)
}/ (x_{x}-x_{1})

Substituting the values from our two points, we get

m = [(-8)-(-4)] / [(-7)-(-6)] = (-4)/(-1) = 4,

Now, we have that our equation is: y = 4x +b

In order to find the value of "b", we substitute the values of any of the two points in the above formula and solve for "b",

y = 4x + b

-4 = 4(-6) + b

-4 = -24 + b

-4 + 24 = b, therefore, b = 20

So, now our final equation looks like: y = 4x + 20

Madario, it seems you having a hard time with lines, points, slopes...

Purple math has great explanations for these at

The slope intercept form is

y = mx + b

But you were only given two points on the line, so first you must determine the slope this can be sloved by using the slope formula

m = (y_{1}-y_{2}) = ((-4)-(-8))/((-6)-(-7)) = ((-4)+8)/((-6)+7) = 4/1 = 4

(x_{1}-x_{2})

now that you have the slope you can determine b, the y intercept, by solving for b using the calculated slope and one of the points

y = mx + b

-4 = 4(-6) + b

-4 = -24 + b

-4 + 24 = -24 + b + 24

20 = b

so you can now substitute in the values for m and b that you calculated

y = 4x + 20

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