Mark M. answered • 09/12/15

Mathematics Teacher - NCLB Highly Qualified

For x > 3, y > 0, and xy > 0

For 0 < x < 3, y < 0, and xy < 0

For x < 0, y < 0, and xy > 0.

Since negative numbers are less than positive numbers the possible x values are such: 0 < x < 3.

Mark M.

09/11/15