Andrew M. answered • 08/30/15

Tutor

New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

Let's assign some variables to represent Pepperoni pizzas and Ham & Pineapple pizzas.

For ease P = pepperoni pizza, H = Ham & pineapple pizza.

We can represent the equations by relating them to the amount of calories they contain.

eqn 1) (1/2)P + (3/4)H = 765

eqn 2) (1/4)P + H = 745

Since I don't particularly enjoy working with fractions let's multiply both equations by 4

to get rid of the fractions:

4(eqn 1): 2P + 3H = 3060

4(eqn 2): P + 4H = 2980

To eliminate one variable multiply the new 2nd equation by -2 and then add the equations

2P + 3H = 3060

-2P - 8H = -5960

----------------------

-5H = -2900

H = -2900/(-5) = 580 calories

**The Ham and Pineapple pizza has 580 calories**

We can substitute the value 580 in place of H in either of our

original equations. I will use 2P + 3H = 3060

2P + 3(580)= 3060

2P + 1740 = 3060

2P = 1320

P = 660 calories

**A pepperoni pizza has 660 calories**