A) y= 2/5x+9 write an equation that is parallel to the given line and passes through the point (0, 2)

B) Write an equation that is perpendicular to the same line but passes through point (0, 3)

A) y= 2/5x+9 write an equation that is parallel to the given line and passes through the point (0, 2)

B) Write an equation that is perpendicular to the same line but passes through point (0, 3)

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A lines are paralell when the slopes are equal all we need to do is tell the graph togo through (0,2)

y=mx+b ;

m= slope,

x and y are the cordinates given, (0,2) respectively,

b is what we can change to make the line go through the right point.

plug in the coordinates to find the matching b value.

2=2/5(0)+b

2=0+b

b=2

eq. for parallel line

y=2/5(x)+2

same idea for a perpedicular line except for to be perpedicular the second line's slope must be a recipricol and oppositely signed.

To get the slope you flip the original and multiply it by -1.

Then whats left is to find b again using your new slope.

using form y=mx+b , m is slope, b is y-axis intercept (a point on the gaph where x=0)

A) Two lines are parallel, they have same slope

y=2/5x+9 has slope 2/5, the new line has slope 2/5 too

the new line pass through point (0,2), b=2

solve A: y=2/5x+2

B) Two lines are perpendicular, if line1 slope m_{1}, line2 slope m_{2} m_{1}=-1/m_{2
}

y=2/5x+9 has slope 2/5, so the new line has slope -1/(2/5)=-5/2

new line pass through point (0,3), the y-axis intercept is 3

solve B: y=(-5/2)x+3

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## Comments

Thank you :)