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what is the answer for x+2/x^2-x-2 times 3x-6/x-3

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2 Answers

Dear Melody,
Let me try. I have interpreted your question three different ways. Please feel free to chime in and correct me if I mis-interpret your question:
[(x+2)/(x^2)]-x-2 times (3x-6)/(x-3)--> [solve the left side first by factoring (x^2)/(x^2) to (-x-2)]-->simplify to: [x+2-(x^3)-2(x^2)]/(x^2) -->simplify further to: [-(x^3)-2(x^2)+x+2]/(x^2)-->simplify further to: -[(x+1)(x-1)(x+2)]/(x^2)--> now multiply with in the right side and get: -3[(x+1)(x-1)(x+2)(x-2)]/[(x^2)(x-3)] Note: the possible values of x are: -1, 1,-2,2 and the impossible values of x are: 0 and 3.



Stephan V. 

Hi Melody -- we may begin by factoring ... (x+2)/(x-2)(x+1) * 3(x-2)/(x-3) ... (x-2) elements cancel ...

3(x+2)/(x+1)(x-3)  or  3x+6/(x^2 -2x -3) ... Best wishes, ma'am :)