a. x=-6

b. x=6

c. x=-4

d. x=4

a. x=-6

b. x=6

c. x=-4

d. x=4

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Hi, Maira.

The vertex form of a parabola is written** y = a(x-h) ^{2} + k** where

The x-coordinate of the vertex, or **h**, also represents the axis of symmetry.

So in your problem **y=-2(x+w)^2+6**, the axis of symmetry would be
**x = -w** (Note that in the general form it is** x - h** inside the parentheses, so the sign changes.)

Hope this helps!

## Comments

Hi Maira. Are sure, that you copied the function correctly?