a. x=-6
b. x=6
c. x=-4
d. x=4
a. x=-6
b. x=6
c. x=-4
d. x=4
Hi, Maira.
The vertex form of a parabola is written y = a(x-h)^{2} + k where h and k are the coordinates of the vertex of the parabola.
The x-coordinate of the vertex, or h, also represents the axis of symmetry.
So in your problem y=-2(x+w)^2+6, the axis of symmetry would be x = -w (Note that in the general form it is x - h inside the parentheses, so the sign changes.)
Hope this helps!
Comments
Hi Maira. Are sure, that you copied the function correctly?