a. -20
b. 28
c. 24
d. -22
a. -20
b. 28
c. 24
d. -22
Hi, Maira.
The discriminant is the part of the quadratic formula that is under the radical sign, that is, b^{2}-4ac. You can use it to determine how many real solutions the equation has.
First, bring all the terms to one side of the equation:
6x^{2} - 2x + 1 = 0
a = 6
b = -2
c = 1
b^{2} - 4ac = (-2)^{2} - 4(6)(1) = 4 - 24 = -20
The discriminant is -20. (This also tells you that there are no real solutions to this equation.)
Hope this helps!
To put the equation, 6x^2 = 2x - 1 into the standard quadratic equation form, that is: ax^2 + bx + c = 0, subtract (2x - 1) from both sides to yield 6x^2 - 2x + 1. Then, a = 6, b = -2, and c = 1. The discriminant indicates the nature of the equation's roots (complex or real) and is defined as b^2 - 4ac. The discriminant becomes (-2)^2 - 4*6*1 = 4 - 24 = -20. Therefore, the answer is a. Note that the negative value indicates that the roots to this equation are complex.
6x^{2} = 2x – 1
6x^{2} – 2x + 1 = 0
a = 6, b = - 2, c = 1
D = b^{2} – 4ac
D = (- 2)^{2} – 4 • 6 • 1 = 4 – 24 = - 20
So, the answer is (a)