What is the probability of pulling two C's out of the hat with replacement?

What is the probability of pulling two C's out of the hat without replacement?

What is the probability of pulling two A's out of the hat without replacement?

What is the probability of pulling two C's out of the hat with replacement?

What is the probability of pulling two C's out of the hat without replacement?

What is the probability of pulling two A's out of the hat without replacement?

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Saugus, MA

1 A, 2 B's, 4 C's

probability of 2 C's with replacement:

(4/7)(4/7)=16/49

probability of 2 C's without replacement:

(4/7)(3/6)=(4/7)(1/2)=(4/14)=2/7

probability of 2 A's:

0 because: (1/7)(0/6)=(1/7)(0)=0, in other words it's not possible without replacement because you only have one A

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## Comments

back into the hatbefore drawing from the hat again. "Without replacement" means that, once you draw an A, B, or C from the hat, youdon't put it back into the hat.