The vertex of a parabola is (-2, -20), and its y-intercept is (0, -12). equation of the parabola is y = ____x2 + ____x + ____.
The vertex of a parabola is (-2, -20), and its y-intercept is (0, -12). equation of the parabola is y = ____x2 + ____x + ____.
32-8+2-1/2+.... a) 128/9 c) 128/5 b) 256/5 D) 128/3
S=9,a1=3 I need help with this Algebra 2 Problem please
S=9, a1=3
1) log 5/12 write the log equations for each then solve using logs 2) x=5th square root (72.43)*3rd square root (.00035)^2 divided by the 6th square root (5.84) 3)2.35^x=342.7
1) log 5/12 Write the log equations for each then solve using logs 2) x=5 square root (72.43)* 3 square root (.00035)^2 all divided by six square root 5.84 3) 2.35^x=342.7
1) log 5/12 Write the log equations for each then solve using logs 2) x=5 square root (72.43)* 3 square root (.00035)^2 all divided by six square root 5.84 3) 2.35^x=342.7
Using arc length formula (s=r*Θ), it is to my understanding the problem would become [s=1260*(π/6)] with 1260 as the radius and (π/6) as the central angle/theta. Simplified out this should come...
∑8 12 (1/3)^ n-1 n=1
10^5t=2 a) t=2/5 b) t=log4 64 c)t=5log2 d) t=log2/5
Problems go like this: 16x6y4 4√--------- 81x2y8 Just need some help making them into the simplified expressions.
2x/2x-3 - x/4x2-9
Simplify x3+8
algerbra2
determine the vertex of the para bola defined by the function f(x) = 5x^2 + 3x+ 1
PROBLEM QUESTION 1.f(x)=(2x-8)/(3x-12)(2x-8) 1.Determine discontinuity and domain 2.f(x)=x-3/3x^2-7x-6 2.The discontinuities exist at x= and x= The hole in the graph exist at x=...
I'm confused on how to do this equation. It's for my algebra 2 class. Any help would be greatly appreciated
find the angle that is less than 360 degrees and coterminal with 45 degrees.
Suppose θ is an angle in standard position And cos θ=-1/2 and sinθ=-square root of 3 over 2. Can the value of θ be 60 degrees? Can it be -120 degrees ?
let tanθ=square root of 3 over 5, find the other five trigonmetric functions.