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Robert W.

Experienced Math Tutor

Experienced Math Tutor

$75/hour

  • 85 hours tutoring

  • Hannibal, NY 13074

About Robert


Bio

Hi, my name is Rob. I graduated from SUNY Oswego summa cum laude with a BS in applied mathematics and a minor in statistics. I'm currently working as an actuarial consultant.

I was trained as a math tutor in 2010 and have since tutored privately, at Cayuga Community College, and at SUNY Oswego. I have also worked as a teaching assistant for an intro statistics course. My experiences tutoring include one-on-one for algebra, calculus, precalculus, geometry, trigonometry, discrete...

Hi, my name is Rob. I graduated from SUNY Oswego summa cum laude with a BS in applied mathematics and a minor in statistics. I'm currently working as an actuarial consultant.

I was trained as a math tutor in 2010 and have since tutored privately, at Cayuga Community College, and at SUNY Oswego. I have also worked as a teaching assistant for an intro statistics course. My experiences tutoring include one-on-one for algebra, calculus, precalculus, geometry, trigonometry, discrete mathematics and statistics, as well as drop-in math help, with topics ranging from arithmetic to calculus 2. I am more than happy to break out my real analysis, abstract algebra and other high level notes if someone wants help with upper division classes. I am also familiar with grade school level arithmetic and word problems.

My usual style is to first let you work through a problem as best as you can. This helps identify problem areas which we can work on together. After going through examples aimed specifically at increasing ability in those issues, we can try a similar problem. I find it to be very helpful having someone who can identify where the problem is, and can go through a simpler example which highlights the area needing work.


Education

SUNY Oswego
Applied Mathematics

Policies

  • Hourly rate: $75
  • Tutor’s lessons: In-person
  • Travel policy: Within 20 miles of Hannibal, NY 13074
  • Lesson cancellation: 2 hours notice required
  • Background check passed on 2/6/2013

  • Your first lesson is backed by our Good Fit Guarantee

Schedule

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Subjects

Corporate Training

Statistics

Homeschool

Algebra 1, Algebra 2, Calculus, Geometry, Prealgebra, Statistics

Math

Discrete Math,

Discrete Math

As a mathematics major, I am well familiar with the topics covered in discrete mathematics. This class is the gateway to the higher math classes. The topics introduced here are revisited over and over as one works with mathematics, and are crucial to understand. I am well familiar with the topics covered in this class, including laws of probability, combinations, permutations, subsets, power sets, relations, and types of functions. I'm also prepared to assist in learning the proofs necessary for this course, including but not limited to induction, contra positive, contradiction, and if-and-only-if type proofs. The following is a proof done by me on antisymmetric relations, followed by a shorter proof on set intersection of set differences. Set notation is displayed as "?" on this site, obscuring details A relation R on a set A is antisymmetric if and only if R n R-1 ? {(a, a): a ? A}. It will first be shown that if R n R-1 ? {(a, a): a ? A}, R on A is antisymmetric. Suppose R n R-1 ? {(a, a): a ? A}. Let R = {(x, y): x, y ? A}. By definition of inverse relation, R-1 = {(y, x): x, y ? A}. By definition of subset, if (x, y) ? R n R-1, (x, y) ? {(a, a): a ? A}. Hence, x = y, and so (x, y) ? R implies (y, x) ? R. Since x = y, ? (xRy ? yRx), x = y. Thus, by definition of antisymmetric, R on A is antisymmetric. Therefore, if R n R-1 ? {(a, a): a ? A}, R on A is antisymmetric. It will now be shown that if R on A is antisymmetric, R n R-1 ? {(a, a): a ? A}. Let m, n ? A. Suppose that R on A is antisymmetric. Let R = {(m, n): m, n ? A}. Therefore, by definition of inverse relation, R-1 = {(n, m): m, n ? A}. Let (m, n) ? (R n R-1). By definition of intersection, (m, n) ? R and (m, n) ? R-1. Because (m, n) ? R-1, (n, m) ? R. Therefore, (m, n) ? R and (n, m) ? R. Since by definition of antisymmetric, (mRn ? nRm) implies m = n, then m = n. Notice that m and n are equal elements of A, and that (m, n) ? (R n R-1). Therefore, ? (m, n) ? (R n R-1), (m, n) ? {(a, a): a ? A}. Thus, by definition of subset, (R n R-1) ? {(a, a): a ? A}. Therefore, if R on A is antisymmetric, R n R-1 ? {(a, a): a ? A}. It has been shown that if R n R-1 ? {(a, a): a ? A}, R on A is antisymmetric. It has also been shown that if R on A is antisymmetric, R n R-1 ? {(a, a): a ? A}. Therefore, a relation R on a set A is antisymmetric if and only if R n R-1 ? {(a, a): a ? A}. Given that A and B are sets, (A - B) n (B - A) = { }. Let A and B be sets. Suppose, for the sake of contradiction, (A - B) n (B - A) ? { }. Let x ? (A - B). By the definition of symmetric difference, x ? A and x ? B. Since (A - B) n (B - A) ? { }, by definition of intersection, ? at least one arbitrary element, x, in (A - B) and (B - A). By definition of symmetric difference, if x ? (B - A), x ? B and x ? A. ==><==. Observe that if (A - B) n (B - A) ? { }, x ? A and x ? A. Because this cannot be true, it is not true that (A - B) n (B - A) ? { }. Therefore, (A - B) n (B - A) = { }.
Algebra 1, Algebra 2, Calculus, Geometry, Prealgebra, Statistics, Trigonometry

Most Popular

Algebra 1, Algebra 2, Calculus, Geometry, Prealgebra, Statistics

Summer

Algebra 1, Algebra 2, Calculus, Geometry, Statistics

Resources

Robert has shared 1 article on Wyzant Resources.

Go to Robert’s resources

Ratings and Reviews


Rating

4.9 (37 ratings)
5 star
(35)
4 star
(2)
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1 star
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Reviews

Best Trig Tutor

Because of Rob's patience he was able to prep my daughter in just 4 weeks for the Trig Regents. She was able to pass this time. Would recommend Rob!!!!!

Lisa , 4 lessons with Robert

Very helpful!!

Robert saved me with my online statistics class. I wasn't making sense of it on my own, but he had a way of explaining things that I could actually understand what was going on. Robert was so patient and helpful, it really made up for the lack of a classroom. I'm lucky I found him in time for my final! Highly recommended!!!

Stacey, 1 lesson with Robert

Excellent tutor!

Robert just finished tutoring my son in calculus. As soon as we contacted Robert he set up a meeting location and a time. He was always punctual, professional, and easy to reach. Best of all, he is very personable; my son really likes him. Robert is very knowledgeable about the material and seems to enjoy it, so that my son enjoyed learning it. To quote my son "That hour goes by SO fast!" I will definitely use Robert again if I need to and will recommend him to my friends.

Marsha, 10 lessons with Robert

$75/hour

Robert W.

$75/hour

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