Physics makes the world go 'round (literally)! My name is Thomas and I'm currently an adjunct Physics instructor at Cypress College. I have 9 quarters (3 full years' worth) of teaching experience at UC Irvine, which includes leading guided group problem-solving discussions, one-on-one tutoring, and instruction in undergraduate lab courses. No student in the 21st century - whether they're serious about getting a career in

science/engineering, being able to pass crucial exams or simply wanting to expand your intellectual horizons - should go through life without a basic but firm foundation in Physics. Having tutored students from many different majors and levels of familiarity with

math and science, I firmly believe that anyone can succeed with proper guidance.

In order to optimize my tutoring sessions, I will guide the student through a brief self-assessment of his/her learning strengths and weaknesses. I also seek to build on these strengths by creating a learning environment that minimizes rote learning and focuses on stretching the student's thinking and problem-solving instincts by guiding them to the solution via a series of questions. Training the student to break down a large problem into a series of "bite-sized" questions is the key to boosting their confidence and ability to succeed not only in Physics, but in a great number of other subjects as well.

My passion is for helping newbies to get a handle on Physics for the very first time, but I am also eager to help in any other way I can. I also have experience in general

SAT and

GRE preparation, so feel free to contact me about any or all of my listed teaching subjects and we'll work something out.

##### Cancellation

6 hours notice required
*$10 per additional student per hour, up to 3 students total per tutoring session. $55/hr for commitment of 1 hr or more per week for 5 weeks+.*

##### Travel Radius

Travels within 10 miles of Irvine, CA 92612
Tutors have the ability to create educational resources and share them with the WyzAnt community.
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Hi Gayla,
When the problem asks you to evaluate g(5), this simply means you look at the function g(x) and replace all the x's with a 5 and then solve. Since
g(x) = 4x+7,
substitute x=5 and you'll get
g(5) = 4*5+7 = 20+7 = 27
So your final answer is
g(5)...

Hi Gayla.
There are 2 ways you can solve this problem. The first way is to factor the expression x2+6x+8 into the form (x+u)(x+z). If you multiply (x+u) and (x+z), you will get x2+(u+z)+u*z. Therefore,
x2+(u+z)+u*z = x2+6x+8
By...

Dividing a polynomial by another polynomial using long division is very similar to long division with numbers. The only real difference is that you need to keep the same powers of x lined up with each other so you don't get confused. You will also need
to make sure that you are subtracting...