What is the approximate solution of 7^x=3^x+1?
I've tried to use log(10) to bring the exponents to the front but I keep ending up canceling out my variables.
I've tried to use log(10) to bring the exponents to the front but I keep ending up canceling out my variables.
Zero is less than or equal to x and x is less than 360 I tried using different double angle identities but I can't figure out which to use and how to use it.
I've simplified it down to (a/3a+1)+(3/4(a^2-1)) but I don't know if I did right first step because I'm not sure where to go next.
I've added and subtracted 2(pi) but I'm confused on why when I do the negative angle I need to minus 4(pi) instead of 2(pi). Plus in the back of my textbook, the answers say suggested answers...
I'be tried this problem several times and keep getting stuck. I don't think I'm starting it right.
I've multiplied it out so that they both have a common denominator of (x+4)(x-2) and now I'm confused on what to do next.
I know you could plug everything in and figure it out that way but I can't do that because I don't have another point on the parabola. For example: vertex:(-1,-3) focus:(-1,0)
I know the standard form of a circle is (x-h)^2+(y-k)^2=r^2 but I don't see how to put x^2+y^2=x+2 into that form.
I tried to multiply the 3-i on the top and bottom but then I get lost on what belongs on the bottom and on the top. I thought I would have something like 6-2i/9 but that doesn't...
I thought you would just take out the 3 and make it 3(x^3-64) but then I remembered these are the ones that would be 3( )( ) but I cannot get my answer into that form....
I tried to find the inverse but in all my multiplying, it ended up not being a inverse matrix and instead a random set of fractions in my matrix.
I've tried getting the slope which was 3 over 3, simplifying to 1. But when I put it into the basic y=mx+b I got one for b with one set of coordinates and then 7 for the other and I am not sure...