how a protractor should use for finding the angle of partially rhombus like shape?
howw stuck here for many hours..
howw stuck here for many hours..
but i did in this way (9/2)-(13/4) ...
as (-5/10) and secondly there are some questions in which we did this procedure (2 * 5 / 2) - (3 * 1 / 4) ( 9 / 2 ) - (5 / 4 ...
5 *2 / 5 - 3*2/10 =5-3 * 2 / 5 - 2 / 10 =2 * 2 / 10 now look the same question with other way, 27 /5 - 32 / 10 = -5 / 10 so both method are...
6*1/6 - 1*17/24=6-1*1/16 - 17/24 , = 5 *1/6 - 17/24 , = 3-34/48 , = 31/48 ANSWER NOW THE ALTERTERNATIVE METHOD 6*1/16 - 1*17/24 , = 97/16 - 41/24 , = 291-82/48...
and if there if we want to know the mid of 14 and 15 then there mid would be 14.5 or 0.145 ? explain
how many adges a cone and cylinder has? if a cone has one edge that means a cylinder has no edge ? is both the cone and cylinder has 2 adges ? OR a cone has o edges and cylinder has 2...
and on number line 0.7 and 0.8 where the point o.71 will be.
if the base length of octagon is 30 cm then find the area of the shaded part Shaded part is octagon which is within the rectangle please help me how i draw its pic there is no option of g...
Another perpendicular is from P to QR that is bisecting the QR at right angle. The other perpendicular is from P to S making right angle triangle PM=7 cm find the value of...
there is no option here for making diagram is it?
and A big triangle is bisecting two times in this way as first by perpendicular from top P to base QR making Q K and KR. and other is Q S that is bisecting the triangle( showed in dotted lines...
what is the area of the shaded region remains? i write remains and also written below.