Write the standard form of the conic equation in which Eccentricity = sqr(11)/4 Vertices: (0, 9+4(sqr 5)), (0, 9-4(sqr(5)) I have the answer of x^2 /25 + (y-9)^2...
Write the standard form of the conic equation in which Eccentricity = sqr(11)/4 Vertices: (0, 9+4(sqr 5)), (0, 9-4(sqr(5)) I have the answer of x^2 /25 + (y-9)^2...
The directions are the write the standard form equation of the following conic section in which the foci are (6,1), (6,-11) and eccentricity = 3/5. Please explain how you get the denominator...
I have the answer, but I don't understand how to get it. Could you please help? Could you please explain how you got"so c=1+5=6. I don't understand how you came...