3x^2+4y^2-36x+24y+132=0
3x^2+4y^2-36x+24y+132=0
Side a = 26; Side b = 20; Angle B = 15 degrees
I figured this out using my calculator but I need help solving through it without. (cosX)/(1+sinX)+tanX
tanU-1/tanU+1=1-cotU/1+cotU
csc^2V-cosVsecV=cot^2V
(tanV+1)^2(tanV-1)^2=2sec^2V
tanU(cscU-sinU)=cosU
(tanv+1)^2(tanv-1)^2=2sec^2v