In the last sentence of the word problem, I believe you mean 25% more than how many were killed in 2003 no matter how many people altogether there were then. To determine how many more by percentage, you determine the percentage (%) of the entire number
so that you can use this plus (+)...
If any of the kids have started school yet, you are welcome to check your e-mail since I have sent e-mails to a few contacts to whom I have submitted applications. After all, I have been practicing presenting math tutoring concepts to show off my skills.
You are welcome to read my blogs and answers to questions to see how I have done in them. This is my best way to prove how I would be good...
Hi Courtney! I see that you have an equation of -4y-(5y+6)=-7y+3. Here's how you solve it:
1. Use the acronym PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction).
2. Ask yourself about each of these operations to show your work like this:
Here's a sample addition problem of 2 2-digit numbers:
Referring to that problem above, on a piece of paper, I would make 6 and 8 dots for the place value of ones and 3 and 4 vertical lines for the place value of tens. This would help any kid understand the structure of each number so that he or she could
learn how to add them. To prove that the...
Yes, there is only one way. Let's say for example that we have a fraction of 2/3. Now, the bottom number is the denominator which means the number of equal parts into which a whole circle most specifically is divided. So the circle is divided into 3 equal
parts. On the other hand, the top number is the numerator which means how many equal parts out of all of them are lightly shaded inside...
Well, there are two exceptions to this question. X cannot be 0 or 1 because 0*0=0, and 1*1=1. No matter how many times you multiply 0 by itself, you will always get 0, and no matter how many times you multiply 1 by itself, you will always get 1. That's
why the power of x will never change its value if x is 0 or 1. Now that we realize the two exceptions of 0 and 1 for x, x would have to be in...
+3/8=+3/8 Add 3/8 to both sides to eliminate -3/8 on the left side.
n=1/8+3/8 Fraction addition with a common denominator.
n=4/8=1/2 Final fraction answer in lowest terms since the GCF between the numerator and denominator is 4....
The fraction 15/17 means that a whole is divided into 17 equal parts according to the denominator, and only 15 of those 17 equal parts are seen according to the numerator. Since the numerator 15 is smaller than the denominator 17, that means 15/17 is a
proper fraction. Now, if all 17 equal...
How to add or subtract fractions:
1. Look at the denominators. Are they the same or are they different?
2. If they are different, then that means each fraction is divided into different numbers of equal parts -- so different that you won't know how many equal parts you will end up with...
This word problem is about a triangle whose perimeter is 47 miles. Since it's asking to find the length of each side, then there are 3 unknowns. So here's what we do:
Let the variables S1 be the length of side 1 in miles,
S2 be the length of side 2 in miles,
and S3 be the length of...
This word problem is talking about two guys, Dave and Rick, and their ages. Since their ages are what we are looking for, we will assign two variables, D for Dave's age and R for Rick's age. The equations are as follows:
D = 2*R Dave is now twice as old as Rick.
We have a triangle with unknown lengths of each side. So we will assign 3 variables for all 3 sides of our triangle.
Let s1 = side 1, s2 = side 2, and s3 = side 3.
If you have 4 tens and 19 ones after regrouping, it will look funny when you express it like this:
4 tens 19 ones unlike
1 ten and 9 ones (19)
The reason it looks funny is that you cannot have two digits in one place because there are only 10 digits between 0 and 9 that can go...
Now, the main unknown here is "the # of adult tickets." Another thing that's unknown is the "the # of children's tickets." So, we will assign 2 variables as follows:
Let a = # of adult tickets
and c = # of children's tickets.
The next step is to set up the equations out of the...