Search 74,231 tutors
FIND TUTORS

Grigori S.'s Resources

Answers

You are, probably, asking about meters per second (m/s).  One mile is equal to 1612 meters (some resources use 1610 oe 1609 meters).  Also we have to change 1hour (1h) to seconds. 1h = 3600 s.   Thus, we have       70 mi/3h = 70x1612 m/(3x...

Answers

The degree of your resultant polynomial (no matter they are added or subtracted) is 7. When you are performing your operations with polynomials of different degrees you are combining only like terms (terms with the same degree). The degree of your resultant polynomial is the same like of the...

Answers

Let's rewrite your expression:                          2t+4/(12 -3t^2) = 2(t+2)/3(4 - t^2) = 2(t+2)/3(2-t)(2+t) = 2/3(2-t).   Thus, when t approaches -2 your limit will be 2/12 = 1/6.

Answers

Another way to solve the problem. Your function has the first coefficient with negative sign, which means it may only maximum. The time the ball reaches the ground is double of the time needed to reach to its maximum position. To find that time just calculate derivative of your function and...

Answers

Unit rate for the bathroom faucet - 8/12 ounces/min = 0.75 oz/min = 3/4 oz/min Unit rate for the kitchen faucet - 6/10 = 3/5 oz/min - two rates show different coefficients of proportionality between amounts of water leaked and time.   Unit rate or both faucets = (3/4) + (3/5)...

Answers

To calculate then uncertainty of the equivalent capacitor Ceq you have to differentiate the expression for the capacitor shown by Richard, and replace the symbol of differential by Δ symbol (means uncertainty or error of measurement). Let           ...

Answers

The sky is blue because of Raleigh scattering  of the sunlight  in the Earth atmosphere. This type of scattering (while the other portion of the light reaches the Earth's surface) is described by the function inversely proportional to fourth degree of the light wavelength: ∼λ-4)...

Answers
boat speed (answer)

 GUIDE PROBLEMS Let d be the distance traveled by the boat, v0 - speed of the boat in still water, v - speed of the current, t1 = 1/5, and t2 = 3/5. To find the speed of the boat in still water we have to write two equations: one for motion up the river and another one – against...

1 2 3 4 5