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Nataliya D.'s Resources

    x + y = 3 +     x - y = 7      2x = 10 ----> x = 5   5 + y = 3 ----> y = - 2 5 + (- 2) = 3  5 - (- 2) = 7

√(5x - 1) = 1 + √(x + 2) √(5x - 1) - √(x + 2) = 1 [√(5x - 1) - √(x + 2)]2 = 12 [√(5x - 1)]2 - 2√(5x - 1) * √(x + 2) + [√(x + 2)]2 = 1  5x - 1 - 2√[(5x - 1)(x + 2)] + x + 2 = 1 - 2√[(5x - 1)(x + 2)]...

   x2 - 4y2 + 7 = 0  ..... (1)  3x2 + y2 = 31      ..... (2)  Let's multiply (2) by 4 and add two equations:       x2 - 4y2 = - 7   +   12x2 + 4y2 = 124    ...

(C) a = 0 produces a counter example. If a = 0, then we have f(x) = 0x + b or f(x) = b , which is a horizontal line. Thus, the range (all possible values of "y") is limited to whatever "b" is.

Answers Algbrea 2 Math (answer)

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