(sinxtanx)/(tanx-sinx)=(tanx+sinx)/(sinxtanx)
working with the left side first...
[(sinx)(sinx/cosx)]/(tanx-sinx)
(sin2x/cosx)/[(sinx/cosx)-sinx]
(sin2x/cosx)/([sinx-sinxcosx]/cosx)
(sin2x/cosx)*(cosx/(sinx-sinxcosx)
sin2x/(sinx-sinxcosx)
sinx/(1-cosx)
working...

curved surface of a right cone is given by the formula:
pi*r*√(r2+h2) where r=radius of the base and h=altitude of the cone
find the altitude first
h2+12.52=262
h2+156.25=676
h2=676-156.25
h2=519.75
h=22.8 feet
3.14*12.5*√[(12.5)2+(22.8)2]
3.14*12...

Part 2
(x+9)+(y+5)=64
(x-a)2+(y-b)2=r2
center is (a,b) and radius is r
center is (-9,-5) and radius is√64=8

1+tan2(x)=sec2(x)
1+(-2)2=sec2(x)
1+4=sec2(x)
5=sec2(x)
sec(x)=√5

6x3=2*3*x*x*x
20x4=2*2*5*x*x*x*x
6x3=2*3*x*x*x
20x4=2*2*5*x*x*x*x
GCF=2*x*x*x=2x3

5+5^2+5^3+5^4+...+5^k
5+25+125+625+...+5^k
(5+25)+(125+625)+...+5^k
30+750+5^5+5^6=30+750+3125+15,625=30+750+(3125+15,625)=
30+750+18750 is divisible by 10
looking at the pattern...

call the parts 1,2,3,4, and 5
call the actors A,B,C,D, and E
here are the possibilities for A:
A1, A2, A3, A4, A5
if A does 1, we have A1
here are the possibilities for B:
B2, B3, B4, B5 (A is doing part 1)
if A does 2, we have A2
now here are the possibilities...

n/4=5/6
cross multiply
6*n=4*5
6n=20
n=20/6
n=3 2/6
n=3 1/3

sin(x)+sin2(x)=1
sin2(x)+cos2(x)=1 is a trig identity
sin(x)+sin2(x)=sin2(x)+cos2(x)
sin(x)=cos2(x)
Looking at cos2(x)+cos4(x) we have:
sin(x)+[cos2(x)]2
sin(x)+[sin(x)]2
sin(x)+sin2(x) which equals 1 from your hypothesis above
Therefore...

If the slope is 0, the line is horizontal and parallel to the x-axis.
The point-slope form is y-y1=m(x-x1) for the point (x1,y1).
For example, use the point (2,3).
y-3=0(x-2)
y-3=0
y=3 is the equation of the line. This line is a horizontal line that is parallel to the x-axis...

The equation for a circle is (x-a)2+(y-b)2=c2
The center is (a,b) and the radius is c.
1) center (3,-1) and radius √16=4
2) center (-5/8,-2) and radius √(25/7)=√25/√7=5/√7=5√7/7
3) center (3.2,0.75) and radius √(37.21)=6.1

-14x2+44x-6=0
14x2-44x+6=0
2(7x2-22x+3)=0
7x2-22x+3=0
(7x-1)(x-3)=0
7x-1=0
7x=1
x=1/7
x-3=0
x=3

d=r*t
68=9t+8t
68=17t
68/17=t
t=4 hours

3x-2y=4
x+3y=5
x=5-3y
Now use the substitution method.
3(5-3y)-2y=4
15-9y-2y=4
15-11y=4
Try it from here Daphinee; solve for y by isolating the variable y. Once you have a value for y, replace y by this value in either of the original equations.

2x-3y=-7
3x+4y=15
Multiply the first equation by 3 and the second equation by 2.
3(2x-3y)=3(-7)
2(3x+4y)=2(15)
6x-9y=-21
6x+8y=30
Subtract the second equation from the first equation.
-17y=-51
y=(-51)/(-17)
y=3
Substitute 3 for y in either...

Another way to solve the problem:
Rachel spent 15 % of her money and saved the rest which is 85 % of her money.(100 %-15 %=85 %)
85 % of $40=0.85*40=$34 saved

let x and x+1 be the consecutive pages
x(x+1)=1190
x2+x=1190
x2+x-1190=0
1190=119*10=7*17*2*5
17*2=34 and 7*5=35
35-34=1
(x+35)(x-34)=0
x-34=0
x=34
x+1=35
b. 34 is the answer
Another simpler solution:You are multiplying two...

In a 30-60-90 right triangle, the side opposite the 30º angle is half the measure of the hypotenuse.
Let x=the length of the side opposite the 60º angle.
The hypotenuse has a measure of 24 inches and the leg opposite the 30º angle has a measure of 12 inches.
Using the Pythagorean Theorem:
242=122+x2
576=144+x2
576-144=x2
432=x2
x=20...

The simplest thing to do is find the cube root of 42,735. Use your graphing calculator or trial and error.
The cube root of 42,735 is 34.96186...
Round this to 35. This is the middle number.
The three consecutive odd numbers are 33, 35, and 37.
33*35*37=42,735
The largest is...

Between means non-inclusive, so 100 and 300 are not included in the list of multiples of 5.
There are 20 multiples of 5 between 100 and 200 including 200. There are 19 multiples of 5 between 200 and 300 not including 200 (we already included 200) and not including 300 from the problem stating...