d=r*t 16=(r+2.78)*t (the winner was 2.78 mph faster) 16=(r)*(t+1) ( the loser took 1 hour longer to finish) they are both equal to 16 so set them equal to each other (r+2.78)*t=(r)*(t+1) rt+2.78t=rt+r subtract rt from both sides 2.78t=r substitute...

## Arthur D.'s Resources

Put the numbers in order. 43,46,47,49,50,52,54,78 There is an even number of numbers which means that there are two middle numbers. 49 and 50. There are 3 numbers less than the two middle numbers and 3 numbers greater than the two middle numbers. Find the mean of 49 and 50: (49+50)/2=99/2=49...

(3,8) and (6,6) connect to form a straight line(obviously !) Then... (6,6), (7,8), and (9,12) are all on the same straight line whose equation is y=2x-6. I found the slope (rise/run) first and then the y-intercept (b). The point (12,18) is on this line also but 18 is not one of the choices...

x= Helga's rate (1/2)(1/2)+(1/x)(1/2)=1 1/4+(1/2x)=1 (4x)(1/4)+(4x)(1/2x)=4x(1) x+2=4x 2=3x x=2/3 hr check: assume we don't know how long it takes them to work together(x hrs) (1/2)(x)+(1/(2/3))x=1 (1/2)x+(3/2)x=1 (4/2)x=1 2x=1 x=1/2...

simplify 6(x-7)-x(x-2)+11(x2+2) 6x-42-x2+2x+11x2+22 10x2+8x-20 0.0023601=2.3601x10(-3) (1.25*107)/(2.5*104)=(1.25)/(2.5)*(107)/(104)=0.5*103=500 I don't understand the other problems with the small x and small numbers. Maybe...

8 ft*12 in=96 in 96/8=12 there are 12 8-inch sections if you put one plant at each end, you need 13 plants p p p p p p p p p p p p p l ...

let x=# of pounds of bluegrass let 204-x=# of pounds of ryegrass 11(x)+14(204-x)=13(204) 11x+2856-14x=2652 -3x+2856=2652 -3x=2652-2856 -3x=-204 x=68 pounds of bluegrass 204-68=136 pounds of ryegrass check:11(68)+14(136)=748+1904=$2652...

An incorrect directional degree led to a mistake in my solution. Surendra K. has the correct solution.

an irrational number is a number that cannot be expressed in the form a/b where a and b are integers and b≠0 a rational number is a number that can be expressed in the form a/b a rational number, in decimal form, is a terminating decimal or a repeating decimal an irrational number...

Part A the wall is 18 1/2 ft long the picture is 34 in or 34/12=2 10/12=2 5/6 ft wide 18 1/2-2 5/6=18 3/6-2 5/6 18 3/6=17 9/6 17 9/6-2 5/6=15 4/6 ft left with half this distance on both sides of the picture 15 4/6 simplifies to 15 2/3 (15 2/3)/2=(47/3)/2=(47/3)*(1/2)=47/6=7...

let J= amount of money Jamal has let C= amount of money Caroline has (5/8)J=amount of money Jamal has left (5/8)C=amount of money Caroline has left Jamal had $40 more than Caroline after spending their money (5/8)J=(5/8)C+40 multiply both sides by (8/5) (8/5)(5/8)J=(8/5)(5/8)C+(8/5)(40) J=C+64 Jamal...

let x=# of courtside seats let y=# of end zone seats let z=# of balcony seats set up three equations with three unknowns 15,000=x+y+z 76,000=8x+6y+4z 44,000=(0.5x)(8)+6y+(0.5z)(4) multiply third equation by 2 88,000=8x+12y+4z subtract...

S=2LH+2LW+2WH S-2WH=2LH+2LW S-2WH=L(2H+2W) (S-2WH)/(2H+2W)=L

√(a2+b2)≠(a+b) square both sides of the equation [√(a2+b2)]2≠(a+b)2 (a2+b2)≠a2+2ab+b2 the right hand side has an extra term 2ab

let x= # of new trees (20+x)(116-4x) 2320+116x-80x-4x2 2320+36x-4x2 use -b/2a for the equation in the form ax2+bx+c, or -4x2+36x+2320 -36/(2)(-4)=-36/-8=4.5 trees but you can't have half of a tree so you use 4 or 5 20 trees...

I noticed your problem. If you still need help repost it and I'll do it for you. Here are some hints: log(10)9=log(2)9/log(2)10 (change of base) log(2)9=log(2)32 log(2)10=log(2)[5*2) log(2)[5*2]=log(2)5+log(2)2 (notice log(2)5=x in the original problem and log(2)2=1) Good...

A to B is 5 to 8, B to C is 3 to 4 B=8 and B=3 in the two ratios make the two B's the same number 8*3=24 and 3*8=24 5/8=?/24 and 3/4= 24/? ?=15 in the first equation and ?=32 in the second equation 5/8 becomes 15/24 and 3/4 becomes 24/32 now we have A to B is 15 to 24,...

Do you want ordered pairs that satisfy this equation ? If so, here are some... x=0, y=3, (0,3) x=2, y=6, (2,6) x=-2, y=0, (-2,0) x=4, y=9, (4,9) x=-4, y=-3, (-4,-3) If you want more, pick multiples of 2(positive or negative) for x and solve for y. This will give you integer...

Call the 20 students A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S, and T A plays the 19 other students B plays C,D,E,... for a total of 18 games(he doesn't play A because A played B and they play only once) C plays D,E,F,... for a total of 17 games(he doesn't play A or B because A and B already...

(sinxtanx)/(tanx-sinx)=(tanx+sinx)/(sinxtanx) working with the left side first... [(sinx)(sinx/cosx)]/(tanx-sinx) (sin2x/cosx)/[(sinx/cosx)-sinx] (sin2x/cosx)/([sinx-sinxcosx]/cosx) (sin2x/cosx)*(cosx/(sinx-sinxcosx) sin2x/(sinx-sinxcosx) sinx/(1-cosx) working...