i just dont understand it
Simplifying Expressions Resources
This is for my trig class, and the directions say use the fundamental trigonometric identities to simplify the expression. Thanks for the help!
This is for my trig class and the directions say to use the fundamental trigonometric identities to simplify the expression. Please help!
I don't know how to do algebra can you help me. I have this big exam coming up and im not ready for it.
it says factor the expression 18b^2 + 12b = I don't know how to do this can you walk me threw it
I don't know where or how to start.
What are the two steps for simplifying radicals? Can either step be deleted? If you could add a step that might make it easier or easier to understand, what step would you add?
Whenever math gives you an easy topic, take it and run with it! I am sometimes surprised by how many students struggle (really struggle) with factoring. That said, I always struggled with quadratics when I was in high school. And forgetting to move negative signs and decimals when simplifying (whoops!). Fortunately, I've gotten past that. My point is that even tutors and teachers start somewhere,... read more
you have to simplify and evaluate
How to simplify the following x^8/2y*5y^2/x^3?
I don't know how you can simplify 6x^2 and 4x if the 4x isn't squared like the 6x^2 Thanks a lot :)
Use the product rule to simplify the expression. (-4x^4p^6)(6y^5x^2)
Solve the compound inequality. Type your answer in interval notation. Simplify your answer. -5≤-3x+3/2≤3
Simplify ( 3x^-4/y^-3)^-4
How do u simplify expressions
I am learning how to simplify expressions, how do you find out how to use the divsion symbol on the computer?
((q−1r−1s−6) / (r−3sq−5))−1 Simplify and eliminate all negative exponents.
Hi, Why does the +5 in this equation 4(2p -1) - (p+5)change to -5. There is nothing out side the second parentheses for multiplying. I got the answer wrong I...
x^2(a(a-1)x^(a-2))+4x(ax^(a-1)) How does the expression above simplify to a(a-1)x^a+4ax^a?
Find the general solution of x^2*y"+4xy'+2y=0 that is valid in any interval not including the singular point. Answer: y=c1*x^-1+c2*x^-2 y=x^a y'=ax^(a-1) y"=(a^2-a)(x^(a-2)) x^2((a^2-a)(x^(a-2))+4x(ax^(a-1))+2x^a=0 How...
m(2 + n – m) + 3(3n + m2 – 1) = 33/45 divided by 63/25