Please explain why l1+il = √(1+1) is true? It is a step in working out the question: prove that l(3+i)/(2-i)l = √2.
Please explain why l1+il = √(1+1) is true? It is a step in working out the question: prove that l(3+i)/(2-i)l = √2.
What is the exact value of the above equation in polar form? Please show the steps in how to get to the answer. Thanks.
How do I solve the above equation for x in terms of p? Please show the steps in working it out. thanks.
when a real number and an imaginary number added together equals 0, does both the real number and the real part of the imaginary number have to equal 0?
Writing the expression in factored form.
stander form is a+bi a and b being real numbers
the square roots of 8√3+8i
sqr root (-15+8i)
IF 1,ω+ω²+.....+ωn-1 are the nth root of unity, then the value of (1/x-1)+(1/x-ω) +......+1/x-ωn-1 =________?
If mod z =2, then the points representing the complex numbers -1+5z will lie on a?? 1. circle 2. straight line 3. parabola 4. ellipse
If one vertex of an equilateral triangle is 1+i and centroid is it's origin then other two vertices of triangle are?
4-i/7-i the answer has to be in a+b form. Divided the numerator and denominator by conjugate of the denominator and simplify the resulting expression.
I keep getting i^23=i^20+3=i(4x5)+3=-i It should up -1 but I do not know how
Write the complex number in polar form with argument θ between 0 and 2π. 9 radical 3 − 9i
Write the complex number in polar form with argument θ between 0 and 2π. 7radical 3 − 7i
12) 3i. 3i is the problem i am trying to answer please help me not sure how to do it. It's pre calcus.
The function f : C → C is given by f(z) = z² + 14. What should I do to find the range of this function?
perform each of the following calculations involving complex numbers, and write the answer, simplified as much as possible, in the form a + bi, where a and b are real numbers. 1. (4+2i)...
i am having alot of problems with algebra 2. I'd like help finding some of the answers because I know that no matter how I work it out I will not end up with the right answer.
Hint 1; Complex numbers are not more complicated than any other numbers, just different. Complex number = real number + imaginary number Hint 2; imaginary numbers are not more ethereal than real numbers, just different. Imaginary numbers were invented to solve problems involving square roots of negative numbers. Hint 3; we lied to you when we told you that you cannot take the... read more