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Continue on the good ole' AC Method!

Would you like more ease and grace when factoring polynomials?

Especially when the coefficient on the x2 term isn’t so efficient?

Try the AC Method J for something more tactical than guess n’ check?

Remember the standard form of a trinomial:

a x2 + bx + c

Here’s an example with some integer coefficients

3 x2+ 7x – 20

a = 3 b = 7 c = -20

LET’S SPLIT THAT MIDDLE TERM!

~We will need two integers, m and n, that multiple to equal ac and add to equal b~

We can write this as:

mn = ac and m + n = b

mn = 3(-20) = -60 and m + n = 7

Now let’s make a list to develop crack the code!

mn (-60) m + n (7)

-1 * 60 = -60 -1 + 60 = 59

-2 * 30 = -60 -2 + 30 = 28

-3 * 20 = -60 -3 + 20 = 17

-4 * 15 = -60 -4 + 15 = 9

-5 * 12 = -60 -5 + 12 = 7

We found the match! It looks like -5 and 12 works for m and n.

Does anybody have a clue about how to progress with this information?

Message me your response and we’ll continue on!