Would you like more ease and grace when factoring polynomials?

Especially when the coefficient on the x2 term isn’t so efficient?

Try the AC Method J for something more tactical than guess n’ check?

Remember the standard form of a trinomial:

a x2 + bx + c

Here’s an example with some integer coefficients

3 x2+ 7x – 20

a = 3 b = 7 c = -20

LET’S SPLIT THAT MIDDLE TERM!

~We will need two integers, m and n, that multiple to equal ac and add to equal b~

We can write this as:

mn = ac and m + n = b

mn = 3(-20) = -60 and m + n = 7

Now let’s make a list to develop crack the code!

mn (-60) m + n (7)

-1 * 60 = -60 -1 + 60 = 59

-2 * 30 = -60 -2 + 30 = 28

-3 * 20 = -60 -3 + 20 = 17

-4 * 15 = -60 -4 + 15 = 9

-5 * 12 = -60 -5 + 12 = 7

We found the match! It looks like -5 and 12 works for m and n.

Does anybody have a clue about how to progress with this information?

Message me your response and we’ll continue on!