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# An executive invests \$29,000, some at 6% and some at 4% annual interest. If he receives an annual return of \$1,460, how much is invested at each rate? (answer)

Let x be the money he invested at 6% interest, and y be the money he invested at 4%. Now we know that x+y = 29,000, because that is the total amount he invested. Let's convert the percent annual interest to decimals: 6% = 0.06 and 4% = 0.04. To do this, divide 6% by 100%. The percent signs...

Multiply both sides by x: 2 = 12x. Divide by 12 on both sides to isolate our variable x: 2/12 = x Reducing this fraction by factoring 2 out of top and bottom, we get x = 1/6.

# Needed help with this math problem. (answer)

This question uses what's called the Zero Product Property. It means that if (a)(b) = 0, then either a is 0 or b is 0. (They could both be zero too).   So then, y-3 = 0 or y -6 = 0. Can you finish the problem now?

# how to solve 2c + ab - 3d (answer)

Without any other information, there's nothing you do to simplify this, since a,b,c, and d are all different variables. Is this the entire question?