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Answers by Rebecca M.

Both of the polynomial pieces must be equal to 11.  Thus -7x-2y = 11 and 11x - 2y = 11. Solve the second equation for -2y by subtracting 11 x from both sides and you have -2y =11+11x Substitute this into the first equation where the -2y is and you have -7x + 11 + 11x = 11...

Remember to subtract you change the sign and add. Now the problem is 1/(x-3) +  -2/(3-x) = 4 (x^2-9). Next put the minus sign into the denominator of the second term for 2/-(3-x).  Multiply the minus sign through the parenthesis to have -3 + x and rearrange x - 3.  Now...

Hi Trevor, You make the polynomial into a square by dividing the second term by 2 and squaring it.  22 divided by 2 is 11. And 11 squared is 121.  The completed square for the polynomial is then Z^2 + 22Z + 121.  Thus C must equal 121 for the polynomial to be a square...

3y-8(-19+4y)=65 (answer)

Maranda, To answer systems of equaltions by substitution first solve one varible in terms of the other then substitute in for that varible.  Here solve x-4y = -19 for x.  Add 4y to each side of the equation to have x = -19 +4y.  Substitute this in to the original equation...

Long division of a polynomial is very similar to numerical long division.  Put the numerator polynomial under the division sign and the denominator on the outside:       _3x^3__-5_________________________ X-2) 3x^4-6x^3-5x+10       ...