# 6x^2+2x-3/2=0 (the 6x^2 and 3/2 are square roots) (answer)

Alright, I am going to assume that the equation should look like this: √(6x2) + 2x - √(3/2)=0 If that is the case, then you have to solve a radical equation. You can do that by isolating √(6x2) from the other terms like this: √(6x2) = √(3/2) - 2 Then...