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Answers by Brian B.

It is a quadratic function, which means the graph will be in the shape of a parabola due to the equation being a second degree function.  Is your daughter in Alg1 or Alg2?  Alg2 covers Conics, while Alg1 usually only handles Linear Functions (straight lines) or Quadratics (U-shaped)...

Nicole, The key to using fractions is to keep it simple.  So, you have two and a half of something...lets say a pizza...school is almost out and we need something to eat for the year end party...and your friend brings four and two-thirds amount of pizza...so...how much pizza do we have...

Use Synthetic Division:    -7 | 4   34   39         4    (34-28)    (39-42)    =    4X + 6 - 3/(x+7)   

(Original Price) = (Sale Price) x (1+discount percentage) (Original Price) = ($63) x (1.30) (Original Price) = $81.90  

Kristen.... think of a negative exponent as a halo on a variable or number...if the halo is positive, then it is on the proper side of the division bar....if the halo is negative, then it is out-of-place....move it to the other side of the division bar...in your question above the top variable...

4y/2=y+9, y=? (answer)

Use a Fraction Buster by multiplying both sides by 2.... 4y = 2y + 18.... Combine Like-Terms by subtracting 2y from both sides 2y = 18 Isolate the y be dividing both sides by 2 y = 9........check the answer by plugging it back into the original equation.... 4(9)/2 = (9)...

The symbol ^ is called a hat and it is used to indicate an exponent....such as in your question is would look like "What is the square root of 49x^6.....the answer is 7x^3....depending on your teacher the x^3 should be in absolute value symbols because you took the even root of an even exponent...

Hello Kayla, It looks like Lindsey copied the wrong question.  As for the inequality above, I would divide both sides by 4 vs. distributing the 4...it will save you time and reduce your chances for errors...than subtract 1 from both sides with the last step being divide both sides by...

This is an expression (aka no equal sign) so all you need to do is combined like terms.  In this case, we have "r" and numbers...two positive "r" and six negative "r"  which combined to be four negative "r" plus the numbers which is just 3....final...

v(4x+4)=-1 (answer)

Douglas,Are you trying to solve for the variable "v" or "x"? 

Times both sided by 4, then divide both sides by "b" and lastly take the cube root of both sides. a = (28/bvc^2)^1/3 

Think of factoring out a common factor from both terms: [x(x-8)+1(x-8)] factor out the (x-8) from both terms and we are left with (x-8)[x+1]. 

Since the bases are the same when you move the log(x-1) to the left, we could use the quotient rule of logs to get Log(3x+5)/(x-1)=1...which we can rewrite in exponential form; 10^1=(3x+5)/(x-1)...which gives us 10x-10=3x+5....7x=15....x=15/7