# how do i find the midpoint of the segment with endpoints (7,14) & (-13,-6)? (answer)

Hello Victoria, (Xm , Ym) = ((x1+x2)/2, (y1+y2)/2) = ((7+-13)/2, (14+-6)/2) = ( -6/2, 8/2) = (-3,4)

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Hello Victoria, (Xm , Ym) = ((x1+x2)/2, (y1+y2)/2) = ((7+-13)/2, (14+-6)/2) = ( -6/2, 8/2) = (-3,4)

X-Intercept is the value of x where cross x axis. Another name is the zeros of the function, when y is zero, the graph cross the x-axis The answer is x-intercepts, Nataliya already answer the question. I just add some explanations to it.

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Which question is right (2y)^3+(6y)^2 or 2y^3+6y^2 ? To factor this (2y)^3+(6y)^2 = 2^3 y^3+3^2 2^2 y^2 = 2^2 y^2 (2y+3^2 ) = 4y^2 (2y+9) 2y^3 +6y^2 answered by Nataliya