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Answers by Carol B.

Solve 2^(3x)=4^(x+2) (answer)

To solve this equation, manipulate the numbers so that the base numbers are the same. Since 4 = 2^2 we can rewrite this as: 2^3x = (2^2)^(x+2) Expanding the exponent gives: 2^3x = 2^(2x+4) Now that both bases are the same, we see that 3x = 2x+4 Solving...

4-8x/x+1=8/x+1 (answer)

To solve this equation for x, we should simplify and then combine like terms. Notice that the second term, 8x/x, simplifies to 8 since x/x = 1, so we can rewrite the equation as: 4-8+1 = 8/x+1 Combining the constant terms gives: -3 = 8/x +1 To get the x...

(2+2x^2+4x)/(x^2+3x+2) (answer)

Notice that you can factor a 2 from the numerator to get [2(x^2 + 2x +1)]/(x^2 + 3x +2) Next, we factor both numerator and denominator to get [2(x+1)(x+1)]/(x+1)(x+2) Cancelling (x+1) from both numerator and denominator gives [2(x+1)]/...

what is the polyonimial function for -5, -1, 2 (answer)

Since you are give three zeros, we know we have a 3rd degree polynomial.   Recall that we factor a polynomial in the form of:  (x-a)(x-b)(x-3) = 0 where a, b, and c are the zeros of the function. Thus, your function factors as: (x+5)(x+1)(x-2) = 0 Doing this...

what is 4(x-1)=28 (answer)

x = 8 To solve, first distribute the left side of the equation to get: 4x - 4 = 28 Next, add 4 to both sides of the equation: 4x - 4 + 4 = 28 + 4 4x = 32 Finally, divide both sides by 4: 4x/4 = 32/4 x = 8