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Is sin2xsinx-cosx = -(3root3)/2 true for 7pi/6? Explain.

Determine the solution(s) to the equation root3tantheta + 3 = 1 where 0</=theta</=2pi.

Is sin2xsinx-cosx = -(3root3)/2 true for 7pi/6? Explain.   Here is what I got: sin(2(7pi/6)) = root3 / 2 (0.86602540378) sin(7pi/6) = -1/2 (-.5) cos(7pi/6)...

If theta is in standard position and 0 </=theta</=2pi, determine the value of tan theta, if sin theta =3/5

cos x(2sinx + sqr root 3)(-sqr root 2 cosx + 1) = 0

Assume the point (-2, 10) is on the terminal side of an angle in standard position.

sin(x+y)/sin(x-y)=(a+b)/(a-b) then tanx/tany=?

A surveyor determines that the angle of elevation to the top of a building from a point on the ground is 26.2 degrees. He then moves back 53.9 feet and determines that the angle of elevation is 18...

Find the exact value of the trigonometric function given that tan u = -3/4, pie/2 < u < pie

(31/2)sinx+cosx

I am not havin g any idea to solve it.

Cos2 (2x) - cos2 (6x) = Sin(4x)sin(8x)

tan4x=(4tanx(1-tan2x))/(1-6tan2x+tan4x)

Sin2 (6x) - Sin2 (4x) = sin(2x)Sin(10x)

I'm not asking what it does, and I'm not looking for "tan(angle)=opposite leg/adjacent leg". I'm asking what the actual function is. For instance, using degrees (not radians) tan(22.5)=20...