Is sin2xsinx-cosx = -(3root3)/2 true for 7pi/6? Explain.

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Determine the solution(s) to the equation root3tantheta + 3 = 1 where 0</=theta</=2pi.

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Is sin2xsinx-cosx = -(3root3)/2 true for 7pi/6? Explain. Here is what I got: sin(2(7pi/6)) = root3 / 2 (0.86602540378) sin(7pi/6) = -1/2 (-.5) cos(7pi/6)...

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If theta is in standard position and 0 </=theta</=2pi, determine the value of tan theta, if sin theta =3/5

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cos x(2sinx + sqr root 3)(-sqr root 2 cosx + 1) = 0

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Assume the point (-2, 10) is on the terminal side of an angle in standard position.

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sin(x+y)/sin(x-y)=(a+b)/(a-b) then tanx/tany=?

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A surveyor determines that the angle of elevation to the top of a building from a point on the ground is 26.2 degrees. He then moves back 53.9 feet and determines that the angle of elevation is 18...

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Find the exact value of the trigonometric function given that tan u = -3/4, pie/2 < u < pie

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(31/2)sinx+cosx

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12sinΘ-9sin2Θ

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I am not havin g any idea to solve it.

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Cos2 (2x) - cos2 (6x) = Sin(4x)sin(8x)

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tan4x=(4tanx(1-tan2x))/(1-6tan2x+tan4x)

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Sin2 (6x) - Sin2 (4x) = sin(2x)Sin(10x)

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5cosΘ+3cos(Θ+pi/3)+3

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I'm not asking what it does, and I'm not looking for "tan(angle)=opposite leg/adjacent leg". I'm asking what the actual function is. For instance, using degrees (not radians) tan(22.5)=20...

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please help me soon

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if secA=17/8 and cosecB=5/4 then sec(A+B) can have value ?

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solve the equation for 0 less than or equal to x less than 2 pie