An open-top box is to be constructed so that its base is twice as long as it is wide. Its volume is to be 2300 cm^3. FInd the dimensions that will minimize the amount of cardboard required. Make: Length...
a box has dimensions 5cm,9cm,5cm. What is the surface area. Teacher did not specify which was length, width, height.
Find the surface area of a box with dimensions 5cm,9cm,5cm. I don't know which dimension is length, width, height though.
Mr. Jenkins has cylindrical columns and rectangular prism posts on his front porch. Both have a height of 3.5 feet. The columns have a radius of 0.5 feet. The prisms have a length...
A cardboard shipping container is in the form of a cylinder with a radius of 6 centimeters and a volume of 8595.4 cubic centimeters. What is the length of the shipping container? What...
The cone has a slant height of 20ft and the crock base has a radius of 10ft (use pi=3.14) I basically need to find the height of the cone and then I'll be able to solve it
a cylinder has a surface area of 402 cm^2. The height is three times greater than the radius. What is the height of the cylinder?
what i did: 402 = 2πr^2+2πr(3r) how do i separate r?
suppose the radius and height of a cylinder are both doubled. by how much is the surface area increased, by how much is the volume increased
i dont get how to find the answer
A right rectangular prism has a total surface are of 512. If all of the edges are congruent, find the length of one of them
Help! I don't know how to start!
Determine the minimum surface area of a closed rectangular box with volume 8 ft^3.
Compute the surface area of the portion of the plane 3x+y+2z=6 inside the cylinder x^2+y^2=4. (Answer: 2pi*sqrt(14)) The formula for the surface area of a cylinder is A=2pi*r^2+2pi*r*h...
Compute the surface area of the portion of the cone z=sqrt(x^2+y^2) below the plane z=4. (Answer: 16pi*sqrt(2))
find the told suface area of a square prism is ten
A cylinder has the SA of 308 cm^2. The height is two times greater than the radius. What is the height of the cylinder?
I'm not sure how to solve this.