Compute the surface area of the portion of the plane 3x+y+2z=6 inside the cylinder x^2+y^2=4. (Answer: 2pi*sqrt(14)) The formula for the surface area of a cylinder is A=2pi*r^2+2pi*r*h...
a cylinder has a surface area of 402 cm^2. The height is three times greater than the radius. What is the height of the cylinder?
what i did: 402 = 2πr^2+2πr(3r) how do i separate r?
suppose the radius and height of a cylinder are both doubled. by how much is the surface area increased, by how much is the volume increased
i dont get how to find the answer
A right rectangular prism has a total surface are of 512. If all of the edges are congruent, find the length of one of them
Help! I don't know how to start!
Compute the surface area of the portion of the cone z=sqrt(x^2+y^2) below the plane z=4. (Answer: 16pi*sqrt(2))
A cylinder has the SA of 308 cm^2. The height is two times greater than the radius. What is the height of the cylinder?
I'm not sure how to solve this.
Determine the minimum surface area of a closed rectangular box with volume 8 ft^3.
find the told suface area of a square prism is ten