determine the value of k for which the system x+y+5z=-3 x+2y-2z=3 4x+11y+kz=31 has no solutions. k=?
determine the value of k for which the system x+y+5z=-3 x+2y-2z=3 4x+11y+kz=31 has no solutions. k=?
7 -3 2 14 h 4 h=?
i need help determining if there are no solution, one solution l, or an infinite number of solutions.
I need help figuring out if there are no solutions, one solution or an infinite number of solutions.
{–1.14, 0.57} {-8, 4} {–0.50, –0.88} {–0.72, 1.22}
Let f(x)=3x-1 and g(x)=x^2+4 find (f g)(-2)
1)A car company charges $31 per day to rent a particular type of car and $0.16 per mile. Juan is charged $47.96 for a one day rental. How many mile did he drive? a)121mi b)106mi c)300mi d)269mi 2)...
Determine the nature of the solutions of the equation: 5x^2-6x=-9 a)Two real solutions b) No solutions c)One real solution d)two solutions with imaginary parts ...
I thought it y=-x+6 but don't no how to work it out
How can the graph f(x)=0.3|x-6|+7 be obtained from the graph of y=|x|? a) Shift it horizontally 3 units to the left. Shrink it vertically by a factory of 0.6. Shift it 7 units upward b)...
The number o books in a small library increase according to the function B=6,700e0.03t, where t is the measure of years. How many books will the library have after 2 year(s)? a) 7,693 b)...
Solve (x^2-9)/x<=0 and write interval notation for the solution set. Show careful algebraic work/explanation.
This is for my trig class, thanks for the help!
This is for my trig class. Thanks for the help!
A solution is 10% citric acid. if 3 liters of a 20% citric acid solution are added to it, the result is a solution this is in a ratio of 13 parts citric acid to 102 parts "other than citric acid"...
This is for my trig class, thanks for the help! If you could, could you please show all your work? Thanks again!
This is for my trig class, thanks for the help! If you could, could you please show all your work? Thanks again!
a)log2(log3x)=4 b)ln(x-1)+ln(+2)=1
This is for my trig class. Thanks for the help!
This is for my trig class. Thanks for the help!