Solving 3e^(-2x)=12 2^(x+1)+3=9 2+ln(x+3)=13 Graphing 2+log2(x+1) -log1/2x -2+ln...
Solving 3e^(-2x)=12 2^(x+1)+3=9 2+ln(x+3)=13 Graphing 2+log2(x+1) -log1/2x -2+ln...
This question is really confusing me: If f(x) = 3x-2, Find f(log3a) for a>0 Step-By-Step would be greatly appreciated!
graph y=logx, y=log(10x), and y=log(100x). how do the graphs compare? use a property of logs to show that the graphs are vertical shifts of one another.
7 ln x - 1/4 ln y I would be very grateful for some help! Thanks for reading!