Please check the links below. www.mathportal.org/calculators/calculus/integral-calculator.php?val1=(cos(4x))/(sin(2x)%2Acos(2x))&val2=%5Cdisplaystyle%5Cint+%5Cdfrac%7B%5Ccos%5Cleft(4x%5Cright)%7D%7B%5Csin%5Cleft(2x%5Cright)%7B%5Ccdot%7D%5Ccos%5Cleft(2x%5Cright)%7D%5C%2C+%5Cmathrm+d+x&rb1=indef&val3=pi/6&val4=pi/3 www...

solve for the integral....dx/xsqrt(9-4x^2)

#### Latest answer by

solve for the integral.......cos(x)sqrt(1-cos(x)) in respects to x, lower bound is o and upper bound is pi/2

#### Latest answer by

find the integral of (dx)/(x^7-x)

#### Top voted answer by

∫sin(x)cos(x) dx 1. substitution where u=sin(x) 2. substitution where u=cos(x) 3 .integration by parts 4. using the identity sin(2x)=2sin(x)cos(x)

#### Latest answer by

I'm not asking what it does, and I'm not looking for "tan(angle)=opposite leg/adjacent leg". I'm asking what the actual function is. For instance, using degrees (not radians) tan(22.5)=20...

#### Latest answer by

How to find integral of ∫73√x is there a way you can explain

#### Latest answer by

find the integral 1/ (x* e^x ) dx

#### Latest answer by

∫ -2 dq (cos-1q)√(1-q2)

#### Top voted answer by

0∫2(0∫¶/2 xsin(y)dy)dx

#### Latest answer by

Can you help me in calculating the integral> I= dx/sinx(2+cosx-2sinx) I could really use the help. Thanks to everyone!

#### Answered by

Need help on ∫1/(1-Χ²) from -√2/2 to +√2/2

#### Latest answer by

Evaluate the double integral from 0 to 1 and x^2 to 1 of (x^3)(sin(y^3)) dy dx by reversing the order of integration. I know how to solve the integral, I just don't know how to set up the new...

#### Latest answer by

Find ∫ (sin(6x))2(cos(6x))2 dx.

#### Answered by

Find the improper integral of dx/x^5 from 1 to infinity. Answer: 1/4

#### Latest answer by

int {1/(x^2 Sqrt[1 - b^2/x^2 + (k/E) (exp[-2 a (x - c)] - 2 exp[-a (x - c)])])} dx a,b,c,E,k are parameters

#### Answered by

Se^(3x)cos(2x)dx S=Integral

#### Latest answer by

A problem I am dealing with is finding the Definite Integral, from 1 to 2, of (4x^3 – 3x^2) dx: I understand that you integrate, Plug in upper limit then subtract lower limit. my answer comes...

#### Latest answer by

Find a formula involving integrals for a particular solution of y'''-y"+y'-y=g(t). Answer: Y(t)=(1/2)∫(from to to t) [e^(t-s)-sin(t-s)-cos(t-s)]g(s)ds

#### Latest answer by

......................................................................................................