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# At what point is the tangent line to the curve y^3=2x^2.....

At what point is the tangent line to the curve y^3=2x^2 perpendicular to the line x-2y-10=0 ? (x,y) format

# Find by implicit differentiation.

Find d^2y/dx^2 x^6y^2-4=0

# Given y(2x^3-7)^4

Differentiate by using chain rule y=(2×^3-7)^4

# Find an equation of the tangent line to the curve (x^2)(e^y)+(ye^x)=4 at the point (2,0).

I think you're supposed to use implicit differentiation, and then solve for the equation after finding the slope.

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# calculus question......

the position function s of a point is given by two dimensional quantities  where t in seconds and the y direction is affected by gravity (10m/s/s). y(t)=4t*sin(θ) - 5t2      ...

# Find the point besides the origin where the graph of xy=x+y^2 has a vertical tangent

It's Calculus. Implicit differentiation is used.

# Find the points where the following graph has a vertical tangent line

Find the points where the following graph has a vertical tangent line. 4x2 + y2 -8x + 4y + 4=0