At what point is the tangent line to the curve y^3=2x^2 perpendicular to the line x-2y-10=0 ? (x,y) format
At what point is the tangent line to the curve y^3=2x^2 perpendicular to the line x-2y-10=0 ? (x,y) format
Find d^2y/dx^2 x^6y^2-4=0
Differentiate by using chain rule y=(2×^3-7)^4
I think you're supposed to use implicit differentiation, and then solve for the equation after finding the slope.
.................................................................................................
the position function s of a point is given by two dimensional quantities where t in seconds and the y direction is affected by gravity (10m/s/s). y(t)=4t*sin(θ) - 5t2 ...
It's Calculus. Implicit differentiation is used.
Find the points where the following graph has a vertical tangent line. 4x2 + y2 -8x + 4y + 4=0