find the particular solution of the differential equation f"(x)=6(x-1) whose graph passes through the point (2,1) and is tangent to the line 3x-y-=0 at that point
find the particular solution of the differential equation f"(x)=6(x-1) whose graph passes through the point (2,1) and is tangent to the line 3x-y-=0 at that point
The process I was taught in class was as follows: 1. Transform the second order non homogeneous DE into a system of first order DE. 2. Solve the homogeneous part. 3. Assume the solution...
Attached is the problem from my text book. I'm confused about what I'm actually solving and how to use what I know. I know that Current for the inductor is given by the equation di/dt = v/L and the...
Suppose that an initial population of 10,000 bacteria grows exponentially at a rate of 2% per hour and that y=y(t) is the number of bacteria present t hours later. a) Find an initial-value...
how do you find the second derivative of y=e-x^2
A differential equation is an equation involving a function and one or more of its derivatives. Determine whether the function y=πsinθ+2πcosθ is a solution to the differential equation d^2y/dθ^2...
Answer: c1cos(t) + c2sin(t) -1/3tcos(2t) -5/9sin(2t) Please show the work step by step.
Answer: c1e^-t + c2e^-t/2 + t^2 +6t + 14 -3/10sin(t) - 9/10cos(t) Please show the work step by step.
Answer: c1e^-t + c2t^-t + t^2e^-t
consider the equation f(x)=-6-1 and g(x)=4x^2 select the solution for (fg)(x)
after the coffee is heated to 200 degrees , it is set in a room at 50 degrees.It cools at a rate that is proportional to the difference between its current temperature and that of the surrounding...
Solve the differential equation e^x dx+(e^x cot(y)+2y csc(y))dy=0. M=e^x N=e^x cot(y)+2y csc(y) My=0 Nx=e^x cot(y) Obviously isn't exact. What to do next?
Solve the differential equation y dx+(2xy-e^(-2y))dy=0.
Solve the differential equation dx+(x/y-sin(y))dy=0. I know that the integrating factor is y. y dx+x dy-ysin(y) dy=0 d(xy)-ysin(y) dy=0 How do I integrate this?
Consider the initial value problem: y'+(2/3)y=1-(1/2)t, y(0)=yο. Find the value of yο for which the solution touches, but does not cross, the t-axis.
Find the general solution of ty'-y=t^2*e^(-t), t>0. I got y=(t^-1)(e^-t)(t^3/3+c) but when I simplify that I didn't get the right answer. Please help me with steps.
Name the title of the book, author, edition, ISBN number. Also, what bookstore sells used college textbooks for this? And what math should I take after Differential Equations for physics and engineering...
Solve the differential equation y^(4)-5y"-36y=0. r^4-5r^2-36 (r^2-9)(r^2+4) r=3, -3, 2i, -2i y=c1*e^3x+c2*e^-3x+c3(cos(2x))+c4(sin(2x)) Is that the right answer...
Solve the differential equation y"+4y=0. r^2+4=0 r=2i, -2i Now what?
Solve the differential equation (2xy+y^3)dx+(x^2+3xy^2-2y)dy=0. I got x^2*y+xy^3+yx^2+xy^3-y^2=C but that's not the answer. And is Differential Equations taught after Linear...