Full work out
This problem involves more reading comprehension than math! You need to translate the words of the problem into expressions using only numbers and variables:
Assuming L is length and W is width.
"The perimeter of rectangle is 50 meters" 2L + 2W = 50
"The length of the rectangle is 8 meters less than 4 times the width" L = 4W - 8
Now, plug in the last equation for the L values in the perimeter formula to result in an equation with only one variable: 2 (4W - 8) + 2W = 50. Solve for W:
2 (4W - 8) + 2W = 50
8W - 16 + 2W = 50
10W - 16 = 50
10W = 66
W = 6.6 meters
Plug this value back into the equation for the length of the rectangle: L = 4W - 8
L = 4 (6.6) -8
L = 26.4 - 8
L = 18.4 meters
The dimensions of the rectangle are 6.6 meters by 18.4 meters.