Full work out

## The perimeter of rectangle is 50meters.the length of rectangle is eight meters less than four. Times the width. Find the dimensions of the rectangle

Tutors, please sign in to answer this question.

# 1 Answer

This problem involves more reading comprehension than math! You need to translate the words of the problem into expressions using only numbers and variables:

Assuming L is length and W is width.

"The perimeter of rectangle is 50 meters" 2L + 2W = 50

"The length of the rectangle is 8 meters less than 4 times the width" L = 4W - 8

Now, plug in the last equation for the L values in the perimeter formula to result in an equation with only one variable: 2 (4W - 8) + 2W = 50. Solve for W:

2 (4W - 8) + 2W = 50

8W - 16 + 2W = 50

10W - 16 = 50

10W = 66

W = 6.6 meters

Plug this value back into the equation for the length of the rectangle: L = 4W - 8

L = 4 (6.6) -8

L = 26.4 - 8

L = 18.4 meters

The dimensions of the rectangle are 6.6 meters by 18.4 meters.