I need to know how to solve this quadratic equation. I am supposed to answer it by completing the square.
x^2-2x-2=0
I need to know how to solve this quadratic equation. I am supposed to answer it by completing the square.
x^2-2x-2=0
When completing you must isolate the terms that have x.
x^{2} - 2x = 2
Then you take the coefficient of the "b" term (2x), divide it by 2 and then square it giving you the result of 1. You then add that to both sides so your equation should now read
x^{2} - 2x + 1 = 3
Now simply factor and solve!
(x-1)(x-1) = 3
x - 1 = sqrt(3)
x= sqrt(3) + 1