- equation for a parabola x^2 + 4x -5 = 0
- Does this function have a maximum or a minimum?
- What are the coordinates of the vertex in (x,y) form?
- What is the equation of the line of symmetry for this parabola?

## determine the solution(s) to the equation x^2 +4x -5 = 0

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# 1 Answer

* 2. * a = 1 > 0 , parabola opens up and the vertex is a minimum value of the function f(x) = x

^{2}+ 4x - 5 .

*"x" coordinate of vertex is (-b / 2a) ,*

**3.***= -4 / 2 =*

**x**

**-2**"y" coordinate of vertex is y = (

*)*

**-2**^{2}+ 4 (

*) - 5 =*

**-2**

**-9**(x,y) coordinates of vertex: (-2 , -9)

**4.****x = -2**is the equation of the line of symmetry for given parabola.

**Solutions:**x

^{2}+ 4x - 5 = (x + 5)(x - 1) = 0 --->

**x**and

_{1}= -5**x**

_{2}= 1