Help with math pleaseeee

## What is the y-intercept of the line with the equation 5X+y=9?

# 2 Answers

**Solution**: **(0,9) is the y-intercept point of the line 5x+y=9** To understand why, please read the following step by step solution.

**STEP 1**: **
Read**, **understand **the situation within, **identify** and pull out
**important** **information**.

- The equation of the line is given in the standard form:
**Ax + By = C**, where “A” (5) is a positive integer, “B” (1) and “C” (9) are integers. - The standard form equation is very
, using the same methodology.**useful to determine the y-intercept point and the x-intercept point** - The y-intercept point is the point where a line crosses the y-axis (
*coordinate x=0*). - The coordinates of any point of the given line
**must**satisfy the equation 5x+y=9. So, if we substitute*the coordinates of any point of the line*on its equation,*we must get an identity*!

**STEP 2**: **
Translate ****keywords** to their mathematical symbols:

- The y-intercept point is given by
**(0,y)**. These coordinates must be a solution of the equation 5x+y=9. Therefore, - 5(0) + y = 9 by substituting the coordinates of the point (0,y)

**STEP 3**: **
Set up** and **solve** the equation or problem:

5(0) + y = 9

y = 9 So, the **y-intercept point is (0,9)**

**STEP 4**: **
Check** the solution:

5x+y=9

5(0)+9=9 *by substituting the coordinates of the y-intercept point (0,9)*

9 = 9 It’s an identity. Our point (0,9) is the y-intercept point of the line 5x+y=9

**STEP 5**: **
Curiosities**

- Using the same methodology we can get the x-intercept point (9/5,0) or (1.8,0)
- Graphing the line in a standard form equation: plot the two intercepts points (9/5,0) and (0,9), one is lying on the x-axis, and the other on the y-axis, and draw a line through these two points.
*Easy, isn’t?*

5x+y=9

-5x =-5x. Subtract -5x from both sides

y=-5x+9. Put in slope intercept form y=mx+b

y=-5(0)+9. Look for yup intercept by plugging in 0 for x

y=9 Solve. Y=9. Writing as an ordered pair is. (0,9)