Helpppp with mathhhh pleaseee
What is the positive value of X in the solution set of the equation 3X^2-48=0?
The first step is to add 48 to each side, so you are left with 3x2 = 48
then, divide each side by 3
you should now have x2 = 16
If you take the square root of both, you will get plus or minus 4.
The positive value of x is 4.
so, x=4 , or -x=4 => x=-4
but, as only positive values of x are required, x≠-4