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the equivalent exponential equation of log(7J=k is

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3 Answers

10k = 7

Attn: Switch 7 and k. Don't change the base.

If     logab = x    then    ax = b

What you have is:

       log107 = k     so     10k = 7

(the 'standard' logarithm, when no base is shown, is assumed to be base 10)

just as log(100) = 2, because 10^2 = 100 (10 being the base of the COMMON log), so also we have 10^k = 7